nrgize
Dec 29 2005, 05:14 PM
I've seen this question pop up a few times on here.
I have done a Forum search for it, but can't find it.
I wonder if anyone can help ?
I am trying to find out what these sums work out at.
I have even tried search engines ! Even Jeeves doesn't know!
8 Ohms + 8 Ohms = ???
8 Ohms + 4 Ohms = ???
4 Ohms + 4 Ohms = ???
Many Thanks For your help!
Nathan
DJ Marky Marc
Dec 29 2005, 05:23 PM
8ohms + 8ohms is 4ohms
8 ohms + 4ohms is about 2.7ohms
and
4ohms + 4 ohms is 2ohms
nrgize
Dec 29 2005, 05:38 PM
THANK YOU VERY MUCH
Sorry for all the Q's !!!
Nathan
Paul Smith
Dec 29 2005, 07:25 PM
The above calculations apply if the items are wired in parallel. If they are connected in series then normal maths applies e.g 8 + 8 = 16
Paul
Digital discos
Dec 29 2005, 07:26 PM
Remember that's only if you are wiring them in parallel, if you are wiring them in series simply add the resistances...
DJ Marky Marc
Dec 29 2005, 10:19 PM
| QUOTE |
| Remember that's only if you are wiring them in parallel |
and so you should be when putting speakers on an amp
Steve_Mitchell
Dec 29 2005, 10:33 PM
| QUOTE (DJ Marky Marc @ Dec 29 2005, 05:23 PM) |
8ohms + 8ohms is 4ohms
8 ohms + 4ohms is about 2.7ohms
and
4ohms + 4 ohms is 2ohms |
As per.
superstardeejay
Dec 30 2005, 01:30 AM
The formula for parallel impedance is
1/r(tot) = 1/r1 + 1/r2 + 1/r3 etc
where r(tot) = total impedance
r1, r2 etc are the individual speaker impedances.
(Just in case you need to work out other values you've not mentioned yet!!)
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